AC1NDKQN structure

AC1NDKQN

[15-chloro-11-(trifluoromethyl)-12,13,17-triazatetracyclo[8.7.0.02,7.012,16]heptadeca-1(17),2,4,6,10,13,15-heptaen-14-yl]-(8-methyl-3,4,4a,5,6,7,8,8a-octahydro-2H-quinolin-1-yl)methanone

Also Known As: AK-968/15360725|(11-chloro-7-(trifluoromethyl)-5,6-dihydrobenzo[h]pyrazolo[5,1-b]quinazolin-10-yl)(8-methyloctahydroquinolin-1(2H)-yl)methanone|[11-chloro-7-(trifluoromethyl)-5,6-dihydrobenzo[h]pyrazolo[5,1-b]quinazolin-10-yl](8-methyloctahydroquinolin-1(2H)-yl)methanone|[11-CHLORO-7-(TRIFLUOROMETHYL)-5,6-DIHYDROBENZO[H]PYRAZOLO[5,1-B]QUINAZOLIN-10-YL][8-METHYLOCTAHYDRO-1(2H)-QUINOLINYL]METHANONE|[15-chloro-11-(trifluoromethyl)-12,13,17-triazatetracyclo[8.7.0.02,7.012,16]heptadeca-1(17),2,4,6,10,13,15-heptaen-14-yl]-(8-methyl-3,4,4a,5,6,7,8,8a-octahydro-2H-quinolin-1-yl)methanone|11-chloro-10-[(8-methyloctahydro-1(2H)-quinolinyl)carbonyl]-7-(trifluoromethyl)-5,6-dihydrobenzo[h]pyrazolo[5,1-b]quinazoline

CAS: 489451-83-4
Molecular Formula C26H26ClF3N4O
Molecular Weight 502.1747 g/mol
LogP 6.2079
Topological Polar Surface Area 50.5 Ų
Hydrogen Bond Donors 0
Hydrogen Bond Acceptors 3
Rotatable Bonds 1
Exact Mass 502.1747
Monoisotopic Mass 502.1747
Heavy Atoms 35
Complexity 1332.3586

Chemical Identifiers

CAS Number 489451-83-4
SMILES CC1CCCC2C1N(CCC2)C(=O)C3=NN4C(=C5CCC6=CC=CC=C6C5=NC4=C3Cl)C(F)(F)F

Product Overview

AC1NDKQN (CAS 489451-83-4), with molecular formula C26H26ClF3N4O and molecular weight 502.1747 g/mol. IUPAC: [15-chloro-11-(trifluoromethyl)-12,13,17-triazatetracyclo[8.7.0.02,7.012,16]heptadeca-1(17),2,4,6,10,13,15-heptaen-14-yl]-(8-methyl-3,4,4a,5,6,7,8,8a-octahydro-2H-quinolin-1-yl)methanone.

🧪
Safety Data Sheet (MSDS / SDS) View the Laboratory Chemical Safety Summary (LCSS) on PubChem — includes GHS classifications, hazard statements, first aid measures, and handling precautions.
View MSDS →

AC1NDKQN is a custom synthesis product. We offer services from milligram to kilogram scale.

Request a Quote »
🤖 CoreyChem AI 助手 ×
您好!我是 CoreyChem AI 助手。可以问我产品搜索、询价、样品或技术问题。如何帮助您?